$\mu = 200$
$\sigma = \sqrt{3^2 + 4^2} = \sqrt{25} = 5$
normal distribution
a) E
b) we would fail to reject the null hypothesis. this means that we do not have evidence to suggest there is a significant difference in the effectiveness of the two advertisements, Ad A and Ad B.
c) A
d) C
a) the sample is skewed left
b) 5.5
c) [1,8]
d) B… Q2 is at 6.25, but as it is skewed left, median > mean
29, $\mu = 20$, 100*.8*.2 = $\sigma = 16$
A. the less DF you have, the larger your CI and cv must be to accommodate for the lack of data / sample size
7 → .56